-c^2-5c+8=0

Solution for -c^2-5c+8=0 equation:

-c^2-5c+8=0

We add all the numbers together, and all the variables

-1c^2-5c+8=0

a = -1; b = -5; c = +8;
Δ = b2-4ac
Δ = -52-4·(-1)·8
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{57}}{2*-1}=\frac{5-\sqrt{57}}{-2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{57}}{2*-1}=\frac{5+\sqrt{57}}{-2}
$